Aprēķins: 5ucbjy - 1

F  = 
 
 2* 10^(-7)* μ* I1* I2* l
/ r
F =  
 2* 10^(-7)* μ* I1* I2* l
/ r
FF = 210(7)μI1I2lr\frac{2\cdot 10^{(-7)}\cdot \mu\cdot I1\cdot I2\cdot l}{r}
F =  
 I1* I2* l* μ
/ 5000000/ r
FF = I1I2lμ5000000r\frac{I1\cdot I2\cdot l\cdot \mu}{5000000\cdot r}
F =  
 0.0000002* I1* I2* l* μ
/ r
FF = 0.0000002I1I2lμr\frac{0.0000002\cdot I1\cdot I2\cdot l\cdot \mu}{r}
F =  
 2* I1* I2* l* μ* 10^(-7)
/ r
FF = 2I1I2lμ10(7)r\frac{2\cdot I1\cdot I2\cdot l\cdot \mu\cdot 10^{(-7)}}{r}