Aprēķins: Bzg3aX - 1
S_n =
S_0* (1+
)
S_0* (1+
| p |
| / 100 |
|
S_n = S_0* (1+
)$$S_{n}$$ = $$S_0\cdot (1+\frac{p}{100})$$
| p |
| / 100 |
S_n = S_0+
$$S_{n}$$ = $$S_0+\frac{p\cdot S_0}{100}$$
| p* S_0 |
| / 100 |
S_n = S_0+ 0.01* S_0* p$$S_{n}$$ = $$S_0+0.01\cdot S_0\cdot p$$